任意数字(万亿级别以下)转换为英文表示
逻辑不复杂，但是挺考验编程能力的，万亿(trillion)以下的数字都可以表示，一些比较特殊的case和百度翻译的结果对了很多次 , 数字转化为中文思路差不多 。
package main
import(
"fmt"
"math"
)
func oneToNineteen(num int64){
exps := []string{"one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"}
fmt.Print(exps[num-1])
}
func twentyToNinetyNine(num int64){
if num<20 {
zeroToNineteen(num)
return
}
a,b := num/10,num%10
exps := []string{"twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"}
fmt.Print(exps[a-2])
if b!=0 {
fmt.Print(" ")
zeroToNineteen(b)
}
}
func oneHundredTo999(num int64){
if num<100 {
twentyToNinetyNine(num)
return
}
exps := " hundred"
a,b := num/100,num%100
zeroToNineteen(a)
fmt.Print(exps)
if b!=0 {
fmt.Print(" and ")
twentyToNinetyNine(b)
}
}
func oneThousandTo999999(num int64){
if num<1000 {
oneHundredTo999(num)
return
}
exps := " thousand "
a,b := num/1000,num%1000
oneHundredTo999(a)
fmt.Print(exps)
if b!=0 {
oneHundredTo999(b)
}
}
func oneMillionTo999999999(num int64){
if num<1000000 {
oneThousandTo999999(num)
return
}
exps := " million "
a,b := num/1000000,num%1000000
oneHundredTo999(a)
fmt.Print(exps)
if b!=0 {
oneThousandTo999999(b)
}
}
func oneBillionToInt32Max(num int64){
if num<1000000000 {
oneMillionTo999999999(num)
return
}
exps := " billion "
a,b := num/1000000000,num%1000000000
oneHundredTo999(a)
fmt.Print(exps)
if b!=0 {
oneMillionTo999999999(b)
}
}
func numToEng(num int64){
if num==0 {
fmt.Println("zero")
return
}
if num<0 { fmt.Print("negative ") } //注：int64最小值在取绝对值后会发生越界，数字太大这里不单独处理了 num = int64(math.Abs(float64(num))) if num>1000 && num%1000<100{
num_2 := num%1000
num_1 := num - num_2
oneBillionToInt32Max(num_1)
fmt.Print("and ")
twentyToNinetyNine(num_2)
fmt.Println()
return
}
oneBillionToInt32Max(num)
fmt.Println()
}
func main(){
for{
var num int64
_,err := fmt.Scan(&num);
if err != nil{
fmt.Println("error")
return
}
numToEng(num)
}
}
运行结果：
